Solution: Before diving t=into the solution we need to understand how p-mos and n-mos operates.
p-mos :
PMOS is made with the p-type source(S) and drain(D) and an n-type substrate. It carriers the holes (+ or absence of electrons) when a high-voltage(Logic 1) is applied to the gate, PMOS will not conduct.
When a low voltage(0) is applied in the gate, PMOS will conduct.
n-mos:
NMOS is made with n-type source(S) and drain(D) and a p-type substrate, it's carriers are electrons
When a high voltage is applied to the gate, NMOS will conduct
When a low voltage is applied in the gate, NMOS will not conduct
Hence keeping this in mind, when logic 0 is applied to the Gate of n-mos and p-mos, and 2.9V(Logic 1) to the source, pmos behaved like a wire (conducting) whereas n-mos behaved like an open switch. Hence whatever the volavoltagelied at the source(S) reflected as an output because it was the only shortest path to flow.
When Logic 1 will be applied to both the gates and 2.9 V to the Source (S) then p-mos will behave like an open switch hence Source current won't get a path to flow in any direction and output will be observed as logic 0.
Note: If you have any doubt then please do comment below, I will try my level best to make you understand, before giving a negative feedback, please do comment. If you understood then don't forget to give a positive feedback.
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