Question

Every week a series of ssh attack attempts on homer.wcitac.org is posted to a web page: http://homer.wcitac.org/sec290/hwk2/. Look at it in your browser. Each line represents a failed ssh login attempt for a user that doesn't exist on homer.wcitac.org. Each time you refresh the page, you will get a look at a different part of the log file. Your job is to find and display just the IP address of the first failed password displayed on the page. Since the data changes each time the web page is refreshed, you'll need to generalize your program so that it always displays the first IP address. Note that since the length of the user names will vary, the location of the first IP address will move around a little bit. And, IP addresses vary in length. Be sure to account for this. Program code is written in Python 3.0

it was not specified about Library being used or not

Answer 1

import urllib.request  # Needed to read webpage

link = "http://homer.wcitac.org/sec290/hwk2/"  # web page link
content = urllib.request.urlopen(link).read()  # reading web page source code
logs = str(content).split('<p>')  # splitting the content so as to get first line in the second position of the list
text = logs[1].split(']:')[1]  # splitting first line using ']:'
IP = ''  # to store IP address

text = text.split('from ')[1]  # 'from' followed by space is the last character before IP
# therefore taking the second element after splitting

IP = text.split(' ')[0]  # splitting the rest using space and IP is the first element

print('The first failed IP address is: ', IP)

Output: