Question

20 pts Question 5 The amount of annual snowfall in a certain mountain range is normally distributed with a mean of 70 inches and a standard deviation of 10 inches. What is the probability that the annual snowfall for 1 randomly picked year will exceed 66.73 inches? Round your answer to 3 decimal places 0.327 02 0209 0.791

Answer 1

5)

Solution :

P(x > 66.73) = 1 - P(x < 66.73)

= 1 - P[(x - $\mu$ ) / $\sigma$ < (66.73 - 70) / 10]  

= 1 - P(z < -0.327)

= 0.628