Question

the amount of snowfall in a certain mountain range is normally distributed with a mean of 101 and a standard deviation of 14 inches. what is the probabilty that the mean annual snowfall during 49 randomly picked years will exceed

p(mean excesds 103.8))

Solve problems 3 and 4. 3) The amount of snowfall falling in a certain mountain range is normally distributed with a mean of 101 and a standard deviation of 14 inches What is the probability that the mean annual snowfall during 49 randomly picked years will exceed P(mean exceeds 103.8 inches) = (rounded to four decimal places).

Answer 1

mean = 101, sd = 14, n = 49

$\tiny P(\bar{x}>103.8)=P(z>\frac{103.8-101}{\frac{14}{\sqrt{49}}}) = P(z>1.4)\approx 0.0808$

Hence, 0.0808 is the answer.

This is from z-table.

I hope this will help. Thank you.