Question

Suppose within your Web browser you click on a link to obtain a Web page. The...

Suppose within your Web browser you click on a link to obtain a Web page. The content of the web page is not cached in the local caching server, and the IP address for the associated URL is not cached in your local host either, so that a DNS look-up is necessary to obtain the IP address. Suppose that n DNS servers need to be visited before your host receives the IP address from DNS, and each of successive visits incur round trip delay of RTT1, RTT2 ... RTTn respectively. Further suppose that three images, sized 100KB, 120KB and 80KB respectively, are embedded in the Web page associated with the link, which are stored on the same web server as the web page itself, while the size of the Web page is 4KB. Let RTT0 denote the round trip delay between your computer and the server containing the web page, and let R denote the average end-to-end transmission rate between your computer and the Web server. How much time elapses from when you click on the link until you see the entire content of the web page associated with the link? Your calculation should include all the RTTs and transmission delays and show them in a properly simplified mathematical formula

PLEASE NOTE

This answer below is NOT sufficient enough for the question. The created equation needs to have the size of the images posted in BOLD in the question. Please read question thoroughly. NOTE

Total time elapses from clicking the link and transfer of file/object

= 3RTT0 +RTT1 + RTT2 + RTT3 +…+ RTTN This answer not sufficient

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