Homework Answers
Question 17)
Given that,
Sum of square due to treatment (SST) = 737.9
Sum of square due to error (SSE) = 490.0
Total sample size (n) = 10 + 14 + 11 + 18 = 53
Therefore, degrees of freedom for treatment = 4 -1 = 3
(since there are 4 treatments)
Total degrees of freedom = n - 1 = 53 - 1 = 52
Error degrees of freedom = Total df - Treatment df = 52 - 3 = 49
Now,
MST = SST/Treatment df = 737.9/3 = 246.0
MSE = SSE/Error df = 490.0/49 = 10.0
and
F = MST/MSE = 246.0/10.0 = 24.60
Hence incorrect statement is,
3) MST = 264.0
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There is no other information given other then what is in the
picture. Please help I am having difficulty answering the
question.
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Please type the answer by computer Memory drug Placebo No treatment 70 37 43 50 10 17 23 83 90 97 57 63 30 Mean (Y) Var...
Please type the answer by computer
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{Exercise 13.07} Three different methods for assembling a product were proposed by an industrial engineer. To...
{Exercise 13.07}
Three different methods for assembling a product were proposed
by an industrial engineer. To investigate the number of units
assembled correctly with each method, 30 employees were randomly
selected and randomly assigned to the three proposed methods in
such a way that each method was used by 10 workers. The number of
units assembled correctly was recorded, and the analysis of
variance procedure was applied to the resulting data set. The
following results were obtained: SST = 10,800;...
The problemesenpoon indicates that the samples samples. For these reasons, it is reasonable to condude that the conditions are met. Step 6 Recall that when the conditions for a single factor ANOVA F test for equality of three or more means are met. and the null hypothesis, Ho: , -, , , is true, we use the following test statistic where df, - k-1, df, -N-k MST is the mean square of treatments, MSE is the mean square of errors,...
The following data are from a completely randomized design. Treatment 145 145 145 149134 151 140 129 Sample mean Sample variance a. Compute the sum of squares between treatments. 159 310 142 108.8 134 145.2 b. Compute the mean square between treatments. c. Compute the sum of squares due to error d. Compute the mean square due to error (to 1 decimal), e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers....
There is no other information given other then what is in the
picture. Please help I am having difficulty answering the
question.
[9 total pt(s)] A one-way analysis of variance was conducted on 5 groups. The total standard devation was calculated to be 2. The total degrees of freedom was found to be 13 and the resulting p-value was found to be 0.05. Use the given information to fill out the rest of the ANOVA table. What is the number...
[9 total pt(s)] A one-way analysis of variance was conducted on 5 groups. The total standard devation was calculated to be 2. The total degrees of freedom was found to be 44 and the resulting p-value was found to be 0.25. Use the given information to fill out the rest of the ANOVA table. What is the number of treatment degrees of freedom? 4 [1 pt(s)] You are correct. Your receipt no. is 159-6944 © Previous Tries What is the...
Please type the answer by computer
Memory drug Placebo No treatment 70 37 43 50 10 17 23 83 90 97 57 63 30 Mean (Y) Variance (4 (Y Y) Grand Mean () Grand Variance ((Yy Y)2) 83.4 50.0 16.6 112.3 109.0 112.3 50 892.14 3. (10 points) Students were given different drug treatments before revising for their exams. Some were given a memory drug, some a placebo drug and some no treatment. The exam score are shown below for...
Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST =10,790; SSTR =4,510. a....
Exercise 13.07 Algorithmic as Question 3 of 14 Check My Work eBook Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting...
{Exercise 13.07}
Three different methods for assembling a product were proposed
by an industrial engineer. To investigate the number of units
assembled correctly with each method, 30 employees were randomly
selected and randomly assigned to the three proposed methods in
such a way that each method was used by 10 workers. The number of
units assembled correctly was recorded, and the analysis of
variance procedure was applied to the resulting data set. The
following results were obtained: SST = 10,800;...
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