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L-9m W-5kN/m 200 UC 59.5 40kN Uniform Load W kN/m Span L L/2 Use the diagram...
40KN << Uniform Load W kN/m X Span L L/2 Use the diagram above and the W= 4KN/m and L=8m values assigned to you to: a) Calculate the reactions b) Draw the Shear Force diagram c) Draw the Bending Moment diagram
40KN > Uniform Load W kN/m х Span L 12 Use the diagram above and the Wand L values assigned to you to: a) Calculate the reactions b) Draw the Shear Force diagram c) Draw the Bending Moment diagram L = 5m W = 8kN/m
40kN Uniform Load W kN/m X Span L L/2 Figure 1 SPAN L 6 W 11Kn/m Beam is 200 UB 18.2 Use the diagram above and the W and L values assigned to you to: a) Use your shear force diagram to calculate the Maximum longitudinal Shear Stress and where it occ Ccurs. b) Calculate the longitudinal Shear Stress at d/4 from the neutral axis. Check Figures 283 below this table BENDING MOMENT DIAGLAM Kp/m f:40 zm 7.5 KN-M 90...
A continuous beam ABC shown in Figure 2 is fixed at A. Supports at B and C are rollers. A uniform distributed load 40kN/m is applied force acts downward on the span of BC as shown in Figure 2. The EI of the beam is over the span of AB and a 60kN constant (a) Determine the internal moments at A and B using the slope-deflection method [10 marks] (b) Draw the bending values of bending (c) Sketch the deformed...
The W33 x221 steel simply supported beam is loaded with concentrated loads and uniform load as shown with the load P= 150kip and w = 10kip/ft. For this beam do the following; a) Draw the shear and bending moment diagram b) Calculate the maximum compressive and tensile stress c) Calculate the maximum shear stress P Р 3 ft 3 ft w 10 ft
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distributed load and is supported at points A and B. The beam is constructed from two pieces of steel plate (2 at 80mm x 8mm) that are welded together with 3mm welds. Section properties for the beam are also listed. Given the support reactions as RAv 5.8 kN and RBv 2.2 kN, as well as the shear force...
The simply supported beam is subjected to a uniform distributed load, w of 30 kN/m in the negative y-direction and a point load, P of 15 kN in the negative z-direction. The total length, L of the beam is 6 m. Answer the questions that follow: 'n Eenvoudige opgelegde balk word belas met 'n uniform verspreide belasting van w 30 kN/m in die negatiewe y-rigting en 'n puntlas P = 15 kN in die negatiewe z-rigting. Die totale lengte, L...
For the beam below, let the uniform distributed load (w) be 15 kN/m and the beam spans length (L) be 5 m, and El=1000.0 kN/m . Taking redundant Rgt, use the force method to solve: w В + L L (1) 48 (m) for the primary beam; (2) 888 (m) for the primary beam with redundant Rg= 1 kN; (3) The vertical reaction Rg (kN); (4) The vertical reaction RA (kN); (5) The vertical reaction Rc (kN); < (6) The...
Question 3. A uniform load of intensity 12 kN/m and a concentrated load of magnitude 2.4 kN are supported by a beam ABC with overhang at one end (see Figure 3). Draw the shear-force and bending-moment diagrams for this beam. Also, determine the position of maximum moment with respect to point A. 12 kN/m 2.4 kN A С B -1.6 m -1.6 m -1.6 m
Question 3. A uniform load of intensity 12 kN/m and a concentrated load of magnitude 2.4 kN are supported by a beam ABC with overhang at one end (see Figure 3). Draw the shear-force and bending-moment diagrams for this beam. Also, determine the position of maximum moment with respect to point A. (20 marks) 12 kN/m 2.4 kN A C B -1.6 m -1.6 m -1.6 m I Figure 3