Question

(1 point) For each of the following integrals, select an integration technique that could be used to evaluate the integral. The same answer may occur more than once. x-4 dx 2x2 + 3x - 2 1 dx (4 - x2) sinh*(2x) dx l [ sinh | 28#3x-2 2x2 + 3x - 2 dx x2 - 4 Use a substitution u = 2x^2 Use a substitution x = 2sin(t) Use hyperbolic double angle formulae Use hyperbolic identities and a substitution u = sinh(2x) Use integration by parts Use long division Use partial fractions

Answer 1

هادی ( doc doc- 12x c² +30C-2 2x²430c-2" lo (Espand) Some -Sy doc doc. In 12x-11 + In le+21 does 4 in 1px-11-z'ın (x+21) 10/236-1) tkin letzl-uffln bert] - In(2421) = bg in lzeez) - In/2x41 - blgin/x+2) -%234[ +6 10) lux) dx apply = %= 2 sin lu) Juostodu Pescu) = Yutaulu) Yesten Larc sinlsx) simplity Yufan/areson (% x)): CS Scanned berritz-le can

h) Jsn (4)2 du by.Ssin hucul du - kafesh() simn? (w) - 26. Srinn 4o) du) Ssinh"fu) du = ls (-utl sin(2) 4 =// Coshlul sinnslu) -31% (-utlesin hlzus but u=20 4 4 hoef tash(z)senky23) 2%. %%** *fsho (22) simplity X. [tosh (1x)sinh/2x)-2-3 l-vet %s i hl2.22) 1); kliye sinh? fox / desh(12) - 36(-3x+%shlash]) 22194 sinh2/3x) Cosh[22)-3/6/-3x tlf sinh (ypes) kl 14 sinh? (2x) Cosl72x2 -3%81-23et/fs in hlux !) to CS Scanned with CamScanner

ins 2013-2 -doc -gc²_4 simplify 2002+3-? 236-1 بدله = dx Apply un substitution 4=x-2 쨷 Expand 2443 : 242 S2+2 du Szdy +53% do Sa du=24 Sudu a 3 Inlul : 24+3 Inkul =26-2)+31/3-2) = 2604-22 +3 in 12-2)+cy CS Scanned with CamScanner