What is the acceleration of a proton moving with a speed of 8.0 m/s at right angles to a magnetic field of 1.5 T ?
Using force balance
Fnet = Fm
m*a = q*VxB
angle between V and B = 90 deg
VxB = V*B*sin 90 deg = V*B
m*a = q*V*B
a = q*V*B/m
Using given values:
a = 1.6*10^-19*8*1.5/(1.67*10^-27)
a = 1.15*10^9 m/sec^2
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