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Q2. For the ODE y = Inſx +y], y (1.2)= 1 employ the improved Euler's method...
6. Use Euler's method to approximate the solution to y'= xºy - y at x = 1.2 when y(0) =1. Use a step size of h= .1.
6. Use Euler's method to approximate the solution to y' = xºy - y? at x = 1.2 when y(0) =1. Use a step size of h=.1.
Use Euler's method with step size h = 0.2 to approximate the solution to the initial value problem at the points x = 4.2, 4.4, 4.6, and 4.8. y = {(V2+y),y(4)=1 Complete the table using Euler's method. xn Euler's Method 4.2 4.4 n 1 2 2 3 4.6 4 4.8 (Round to two decimal places as needed.)
Use the improved Euler's method to obtain a four-decimal approximation of the indicated value. First use h = 0.1 and then use h = 0.05. y' = xy + Vy, y(0) = 5; y(0.5) y(0.5) - y(0.5) - (h = 0.1) (h = 0.05)
Use the improved Euler's method to obtain a four-decimal approximation of the indicated value. First use h = 0.1 and then use h = 0.05. y' = 1 + y2, y(0) = 0; y(0.5) h = 0.1 y(0.5) ≈ h = 0.05 y(0.5) ≈
Use the improved Euler's method to obtain a four-decimal approximation of the indicated value. First use h = 0.1 and then use h = 0.05. y = xy + Vy, 7(0) = 5; y(0.5) y(0.5) Ch 0.1) Y(0.5) (h = 0.05) Need Help? Read it Talk to a Tutor
9. Use Euler's Method to obtain an approximation of y(1.2), given 3x + y,y(1) 2, h 0.1 INSTRU
Use a 2 step Euler's method to approximate y(1.2), of the solution of the initial-value problem y' = 1 – 2x2 – 2y, y(1) = 4. If you use a formula, as part of your work you MUST indicate what formula you are using and what values your variables have. y(1.2) =
(a) Use Euler's method with each of the following step sizes to estimate the value of y(0.8), where y is the solution of the initial-value problem y' = y, y(0) = 3. (i) h = 0.8 y(0.8) = (ii) h = 0.4 y(0.8) = (iii) h = 0.2 y(0.8) = (b) We know that the exact solution of the initial-value problem in part (a) is y = 3ex. Draw, as accurately as you can, the graph of y = 3ex,...
dy Use Euler's Method with step size h = 0.2 to approximate y(1), where y(x) is the solution of the initial-value problem + 3x2y = 6x2, dx y(0) = 3.