Solution )
5. We know that the molar mass of aluminium is 26.98 g/mol and that of oxygen is 16.00 g/mol.
So,1 mole of Al₂O₃ therefore has a mass of 2(26.98) + 3(16.00) =
101.96 g.
Divide this into the given mass, to find the number of moles
here:
(69.5g)/(101.96 g/mol) = 5.811 mol.
There are 3 moles of oxygen per mole of aluminium oxide, so there
are
3(5.811) = 17.433 moles of aluminium in the sample.
Then there are (17.433 mol)((16.00 g/mol) = 278.93 g of O.
5. Calculate the mass of oxý gen in a 69.5 g sample of aluminum oxide. 6....
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solve the two questions
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