Question

For the truss shown below determine the force in each member given that the connectors are a frictionless pin at A and a frictionless roller at D. State if the members are in tension or compression. 3 kips 12 ft 99 30° 10 ft- -10 ft- -10 ft- - 5 kips 10 kips

Answer 1

922" 9.812 Pro skors 48:666 top lokabo 10 L We need to find member torces & thar nature deaton at D firdt we will find the components of 3(RO) = Ro conto = 0.5RD Roly = Rp Singo - 0.86G RD EMA zo =) 5xlo +10x20 - Rox0.866 x 30 RD = 9.623 kise (Ro), = 4.812 (Roy = 8.334

Ex - A- (RO), HA= 4.812 eros. - PA - 18 - 8.334 - Rat RA 9.666 Now of we joints will find member forces by method at A fos 4. 0 ore FAT 0 19.866 FABS 0+3= 9.846 PAR 6.866 of 15.502. E Pro - - FAB= 8. 904 FARLOSO - PAS + 4. 612 FAF = 8:904x to – 4.612 25-562 I rar= -0.91 8.905 BC EFR do FBF - 8.904 Sind - FBC = 8.904 -10 FBC = 5.722 15.562 E Fgz0 - 8.904 loso - fBf = 8.909x12 Fer -- 6.866 T5.562

at joint & 6. Bol X Fre BHFFS 0.git na fredine = 6.866-5 frez 1.866 & 15.562 Efr20 - 0.91+ 2.92610 = [FRE 2-2.465) fra at foteht E 2.96 d. FED FEDT - 2.465) 2.1.65 10 erga ( Feazalo) at joint D. FeD B 2.465 E4.812 8.334 foc = fco Sin = 8.334 FED = 8.339 x 15.56 feo a to. zob 12

AB AF forces kies 8.964 - 0.93 - 6.866 5722 FC - 2.465 -2.965 10.808 A B compression (nature) (sign) ve nature - tensile force