Question

How do you solve number 6 and 7?

command Part IV R let R - be a linear transformation given by T(x) = A x Ti - 17 n = surjective m = injective A=11 0 o 1 - T- 2 - 3 ux3 ñ m kernel of T for the find a basis -1 17 Ri=RtR 2 1 -2 -000 --00 Tio 17 R3 = R3-Ru Il -2 - 2 -2 1 | Ry:Rut Ri ( - 17 Re - Ro-RITI I To 1 To 1 1-1 2 -3 J 1 oo Tol - 21 1 Slo 0o-orn- X, S X2 : 25 X3=S * ſoo x-000 : XX @ Dimension of ker(t) = 1 so ker(T): 6 It's neither surjective or injective. ③ Image Crange) T. 70 Dimension in the Kernel T? ③ is vero of in the image N

Answer 1

Guen mam A E -2 -2 RyRy N t tramfr mehan F ^lul' dpace . Cernet A Ax b

2-23 0 9て=ん ..X- not in tker nel T otan from v does not Acalau mulhpluy 2 2 en te ma T