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If L=0.10m, v=2.4m/s, the total resistance of the loop is 0.040Ω, and B=0.75T, find the rate...

If L=0.10m, v=2.4m/s, the total resistance of the loop is 0.040Ω, and B=0.75T, find the rate at which the induced emf delivers electrical energy to the circuit.

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Answer #1

energy delivered rate = power = i2R

where i = BLv/ R

= 0.75 . 0.1 . 2.4/ 0.04

= 4.5 Ampere

SO ENERGY RATE = 0.81 W

L= inductace

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