Question

A Revi Part A Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.120 kg apple toward astronaut 2 with a speed of Vi,1 = 1.07 m/s. The 0.160 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.19 m/s. Unfortunately, the fruits collide, sending the orange off with a speed of 0.943 m/s in the negative y direction. What are the final speed and direction of the apple in this case? Before Vo AEON O ? 01,= 3.9 m/s Submit Previous Answers Request Answer After * Incorrect; Try Again; 10 attempts remaining Part B O AQ R O 2 ? º counterclockwise from the positive x axis

Answer 1

Along horizontal axis,

V1,x = - [(0.12 x 1.07) - (0.16 x 1.19)]/(0.12) = 0.52 m/s

Along vertical axis,

V1, y = (0.16/0.12) (0.943) = 1.26 m/s

Velocity, v = sqrt(0.52^2 + 1.26^2) = 1.36 m/s

B)

Direction, theta = 180 - arctan (1.26/0.52) = 112.43°

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