Question

You do not need to do any calculations for this question. All the calculations have already been done. Just pick an answer and explain how you decided on the answer you picked. An inventor has developed a new, energy-efficient lawn mower engine. He claims that the engine will run continuously for 5 hours (300 minutes) on a single gallon of regular gasoline. From his stock of 2000 engines, the inventor selects a random sample of 20 engines for testing. The engines in the sample run for an average of 293.5 minutes, with a standard deviation of 15.25 minutes. The results of the study are shown in the printout below. The researcher conducts a One-Sample t Test. Ho:p=300 H3 P4300 Variable Sample Mean Standard Error p-value Running Time 293.5 3.410 -191 0.0719 Using the above software output and a 5% level of significance, what is the test's conclusion? a. There is insufficient evidence to reject the claim that the engine will not run continuously for 5 hours on a single gallon of regular gasoline. b. There is insufficient evidence to reject the claim that the engine will run continuously for 5 hours on a single gallon of regular gasoline. C. There is sufficient evidence to conclude that that the engine will run continuously for less than 5 hours on a single gallon of regular gasoline. d. There is sufficient evidence to conclude that the engine will not run continuously for 5 hours on a single gallon of regular gasoline. Explain how you arrived at your answer.

Answer 1

Here P value (=0.0719) is greater than alpha=0.05, so we fail to reject the null hypothesis

Hence we have sufficient evidence to support the claim that mean=300

So correct answer here is

b. There is insufficient evidence to reject the claim that the engine will run continuously for 5 hours on a single gallon of regular gasoline.