Homework Answers
Solution
i) 2NO (g) = N2 (g) + O2 (g)
Initial 0.500 0 0
At equilibrium (0.5 –2x)/2 x/2 x/2
Kc = [N2] [O2] / [NO]2
8.84 = (x/2)2/[(0.5 –2x)/2]2
Or 34.36x2-17.6x+2.21=0
x = 0.214
The concentration of N2 (g) at equilibrium, [N2]= x/2 = 0.214/2 = 0.107 mole/L
ii)
CO (g) + Cl2 (g) = COCl2 (g)
At equilibrium 0.5 atm 0.225 atm x
Kp = PCOCl2 / PCO x PCl2
5.5 = x / (0.5)(0.225)
x = 0.619 atm
The pressure of COCl2 at equilibrium is 0.619 atm.
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