Question

5. Create the following matrix (M) using colon operators, and then transpose M to create a new matrix N. Multiply N by M to create a new matrix Z. Sort the rows of Z in descending order and assign to Y. Write codes to find out the index numbers of 54.54 in the new matrix Y. (20) 1.0 1.4 1.8 2.2 2.1 3.4 4.7 6.0 6.0 3.9 1.8 0.3

Answer 1

Since no language is specified and the question needs to be solved by colon operators, I am assuming its Matlab.

I have shown outputs of M, N, Z, Y after every operation. You can suppress them by using semicolon.

(e.g. N=M' ; )

Here is the working code:

M(1,:) = 1.0:0.4:2.2; %Creating first row of M using colon operators
M(2,:) = 2.1:1.3:6.0; %Creating second row of M using colon operators
M(3,:) = 6.0:-2.1:-0.3; %Creating third row of M using colon operators

M                        %display M

N = M'                   %Transpose of M is N

Z = M*N

Y = sortrows(Z,[-1])     %Sort Z in descending order according to column 1

%%Find position of 54.54 in Y
for i =1:size(Y,1)
    for j=1:size(Y,2)
        if Y(i,j)==54.54
            [i j]
        end
    end
end

Here is the output:

null