Homework Answers
i) from figure yield stress = 250 MPa
so yield load = yield stress * area of specimen = 250 * ( (Π/4) *132) = 33183.07 N = 33.18 kN
ii) modulus of resilience = area under stress strain diagram upto yeild stress
= 1/2 * 0.001 * 250 = 0.125 = 125 kJ/volume
iii) elastic strain = 0.001
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The stress–strain diagram for a steel alloy having an original
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