My data is listed
above. Please help with the last data table.Homework Answers
Panel 1 : Equivalent point number of drops = 98 (not 44)
Panel 2 : Half-Equivalent point number of drops = 44 (not 98)
pH at Half-Equivalent point = 6.0
therefore pKa of unknown weak acid = 6.0
Ka of unknown weak acid = 1 x 10-6
Unknown Weak acid identity = Acetic Acid (Ka = 1.8 x 10-5)
% pKa error = 26.46 %
% Ka error = 94.44 % (Yes it is very high)
Add Answer to:
My data is listed
above. Please help with the last data table.
? CHEM 182 Experiment...
Data Table 2: Titration Curve Values pH Value Trial 1 pH Value Trial 2 pH Value...
Data Table 2: Titration Curve Values pH Value Trial 1 pH Value Trial 2 pH Value (Average) Drops NaOH Added Half- Equivalence Point Equivalence Point ? ? ? ? ? ? 0 2.5 2.5 2.5 10 4.5 4.5 4.5 20 4.5 4.5 4.5 30 4.5 4.5 4.5 40 4.5 4.5 4.5 50 O7 5 5 60 5.5 5.5 5.5 70 6 6.5 6.25 80 12.5 13 12.75 90 13.5 13.5 13.5 100 13.5 13.5 13.5 110 14 14 14 120...
Data and Observations I. Determining the Unknown Acid Sample Size CvOt0ni aid identification code...
Data and Observations I. Determining the Unknown Acid Sample Size CvOt0ni aid identification code of unknown weak acid concentration of NaOH solution, M mass of weighing paper plus unknown acid, g mass of weighing paper, g final buret reading, mL initial buret reading, mL 2.0506M 2.0 Ill. Titrating the Unknown Acid identification code of unknown weak acid concentration of NaOH solution, M 500M determination 1 determination 2 LGS G mass of weighing paper plus unknown acid, g mass of weighing...
I am looking for help with just trial one. I am not sure what equations to use or how to go about even answering these questions. I figure if I can get help with trial 1 I should be able to do trial 2...
I am looking for help with just trial one. I am not sure what
equations to use or how to go about even answering these questions.
I figure if I can get help with trial 1 I should be able to do
trial 2 on my own.
( This week has been really bad, I lost my grandfather, so if you
could "dumb" down the steps as much as possible I would appreciate
it, my brain is just not working...
Can someone help me get my data for parts B and C of my lab report?...
Can someone help me get my data for parts B and C of
my lab report? i think I may understand part B, butpart C has me at
a loss. Thank you
TORY DETERNATION OR FORWARD TABLE 8.3 1st Determination 2nd Determination 3rd Determination volume at equivalence point volume at hall equivalence point k (acid equilibrium constant) average standard deviation C. CONCENTRATION OF THE UNKNOWN ACID TABLE 8.4 Trial 3 Trial 1 Trial volume of unknown acid average molarity of...
please help me fill in the rest of the data table for this lab on Determination...
please help me fill in the rest of the data table for this lab on
Determination of the pKa and equivalent weight of a weak acid
(monoprotic acid). i dont know how to find the equivalent weight
and Ka.
Vid 9/1 ml= 0.09970/ CHMISTRY 127 Determination of the pK, and Equivalent Weight of a Weak Acid (Monoprotic Acid) Part Data Sheet Trial 1 Trial 2 Trial 3 UNKNOWN ACID No. = 25.00ml Vaak wid = 25 ml = 0.025 L...
For each trial with the unknown acid, calculate the following: Here is my data: 2. For...
For each trial with the
unknown acid, calculate the following:
Here is my data:
2. For each trial with the unknown acid, calculate the following Trial 2 a. Moles of NaOH required to reach the equivalence point b. Moles of unknown acid in the beaker c. Molar mass of unknown acid Trial 3 a. Moles of NaOH required to reach the equivalence point b. Moles of unknown acid in the beaker c. Molar mass of unknown acid
QUESTION 1 Minnie Mouse did the Ka by Titrimetry experiment last week. Minnie used 28.63 mL...
QUESTION 1 Minnie Mouse did the Ka by Titrimetry experiment last week. Minnie used 28.63 mL of 0.136 M sodium hydroxide to reach the equivalence point when she titrated 0.3062 g of an unknown monoprotic acid. What is the number of moles of acid that were used? QUESTION 2 The Iron in a sample of iron ore can be converted completely to Fe2+ in aqueous solution, and this solution can then be titrated with KMnO4, as shown: MnO4(q) + 6...
B. DETERMINATION OF THE n pK, OF AN UNKNOWN ACID Wnw TABLE 8.2 2nd Determination 3rd Determinatio...
B. DETERMINATION OF THE n pK, OF AN UNKNOWN ACID Wnw TABLE 8.2 2nd Determination 3rd Determination 1st Determination pH mL of NaOH PH mL NaOH mL NaOH pH B.0 303 2.9 3 19 .42 (0 2 -awa 3.00 727 42 41 166 1210 thl 402 426 | 213 39 4.46 210 .42 113 9 1210.a 13 442 11.4711 1441 11 4 ly 9 I125 102 1G5 115 TABLE 8.3 1st Determination 2nd Determination 3rd Determination volume at equivalence point...
What I have so far for data etc. My question I need help with though is:...
What I have so far for data etc.
My question I need help with though is:
This is my data and what I have so far but this is the
question I actually need help with:
-What ions are present in the titrated solution after the
beginning of the titration but before the equivalence point? How
about after the equivalence point when the conductivity is rising?
Lastly, compare your results from 2 and 4 above with the actual
molarity of...
Experiment 10 An Acid-Base Neutralization Reaction A. Determination of Unknown Acid Concentration Trial Trial 2 Tri...
Experiment 10 An Acid-Base Neutralization Reaction A. Determination of Unknown Acid Concentration Trial Trial 2 Trial 3 Trial 4 Volume of acid 10m 10m 10m 10mL Final buret reading- NaOH (mL) To.8ML 23.8ml 26.2m4 29.4m Initial buret reading- NaOH (mL) Volume of NaOH required to reach the end point. V 10.8m. 13ML 2.4mL 3.2mL Molarity of the acid, M. 10. OmL/108m./23.8mL 26.2mL) Unknown acid number: 16 Molarity of NaOH: Average Molarity of acid 0-1076m Show all calculations for trials 1...
Data Table 2: Titration Curve Values pH Value Trial 1 pH Value Trial 2 pH Value (Average) Drops NaOH Added Half- Equivalence Point Equivalence Point ? ? ? ? ? ? 0 2.5 2.5 2.5 10 4.5 4.5 4.5 20 4.5 4.5 4.5 30 4.5 4.5 4.5 40 4.5 4.5 4.5 50 O7 5 5 60 5.5 5.5 5.5 70 6 6.5 6.25 80 12.5 13 12.75 90 13.5 13.5 13.5 100 13.5 13.5 13.5 110 14 14 14 120...
Data and Observations I. Determining the Unknown Acid Sample Size CvOt0ni aid identification code of unknown weak acid concentration of NaOH solution, M mass of weighing paper plus unknown acid, g mass of weighing paper, g final buret reading, mL initial buret reading, mL 2.0506M 2.0 Ill. Titrating the Unknown Acid identification code of unknown weak acid concentration of NaOH solution, M 500M determination 1 determination 2 LGS G mass of weighing paper plus unknown acid, g mass of weighing...
I am looking for help with just trial one. I am not sure what
equations to use or how to go about even answering these questions.
I figure if I can get help with trial 1 I should be able to do
trial 2 on my own.
( This week has been really bad, I lost my grandfather, so if you
could "dumb" down the steps as much as possible I would appreciate
it, my brain is just not working...
Can someone help me get my data for parts B and C of
my lab report? i think I may understand part B, butpart C has me at
a loss. Thank you
TORY DETERNATION OR FORWARD TABLE 8.3 1st Determination 2nd Determination 3rd Determination volume at equivalence point volume at hall equivalence point k (acid equilibrium constant) average standard deviation C. CONCENTRATION OF THE UNKNOWN ACID TABLE 8.4 Trial 3 Trial 1 Trial volume of unknown acid average molarity of...
please help me fill in the rest of the data table for this lab on
Determination of the pKa and equivalent weight of a weak acid
(monoprotic acid). i dont know how to find the equivalent weight
and Ka.
Vid 9/1 ml= 0.09970/ CHMISTRY 127 Determination of the pK, and Equivalent Weight of a Weak Acid (Monoprotic Acid) Part Data Sheet Trial 1 Trial 2 Trial 3 UNKNOWN ACID No. = 25.00ml Vaak wid = 25 ml = 0.025 L...
For each trial with the
unknown acid, calculate the following:
Here is my data:
2. For each trial with the unknown acid, calculate the following Trial 2 a. Moles of NaOH required to reach the equivalence point b. Moles of unknown acid in the beaker c. Molar mass of unknown acid Trial 3 a. Moles of NaOH required to reach the equivalence point b. Moles of unknown acid in the beaker c. Molar mass of unknown acid
QUESTION 1 Minnie Mouse did the Ka by Titrimetry experiment last week. Minnie used 28.63 mL of 0.136 M sodium hydroxide to reach the equivalence point when she titrated 0.3062 g of an unknown monoprotic acid. What is the number of moles of acid that were used? QUESTION 2 The Iron in a sample of iron ore can be converted completely to Fe2+ in aqueous solution, and this solution can then be titrated with KMnO4, as shown: MnO4(q) + 6...
B. DETERMINATION OF THE n pK, OF AN UNKNOWN ACID Wnw TABLE 8.2 2nd Determination 3rd Determination 1st Determination pH mL of NaOH PH mL NaOH mL NaOH pH B.0 303 2.9 3 19 .42 (0 2 -awa 3.00 727 42 41 166 1210 thl 402 426 | 213 39 4.46 210 .42 113 9 1210.a 13 442 11.4711 1441 11 4 ly 9 I125 102 1G5 115 TABLE 8.3 1st Determination 2nd Determination 3rd Determination volume at equivalence point...
What I have so far for data etc.
My question I need help with though is:
This is my data and what I have so far but this is the
question I actually need help with:
-What ions are present in the titrated solution after the
beginning of the titration but before the equivalence point? How
about after the equivalence point when the conductivity is rising?
Lastly, compare your results from 2 and 4 above with the actual
molarity of...
Experiment 10 An Acid-Base Neutralization Reaction A. Determination of Unknown Acid Concentration Trial Trial 2 Trial 3 Trial 4 Volume of acid 10m 10m 10m 10mL Final buret reading- NaOH (mL) To.8ML 23.8ml 26.2m4 29.4m Initial buret reading- NaOH (mL) Volume of NaOH required to reach the end point. V 10.8m. 13ML 2.4mL 3.2mL Molarity of the acid, M. 10. OmL/108m./23.8mL 26.2mL) Unknown acid number: 16 Molarity of NaOH: Average Molarity of acid 0-1076m Show all calculations for trials 1...
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