Question

Metal sphere A of radius 13.0 cm carries 7.00 uC of charge, and metal sphere B of radius 16.0 cm carries -3.00 uC of charge. If the two spheres are attached by a very long conducting thread, what is the final distribution of charge on the two spheres? 2.87 charge on sphere A Your response differs from the correct answer by more than 10%. Double check your calculations. UC 7.0 charge on sphere B Your response differs from the correct answer by more than 100%. UC Need Help? Read It

Answer 1

sol Given, radius of metal sphere A iss, = 13.0 cm = 0.13m and charge on the metal sphere q = 7:00 uc radius of metal sphere is so = 16.0 cm = 0.16 m and charge on the metal sphere 2₂ = - 3.00 uc If the two sphere are attached by a very long conducting thread the new charge on sphere & and B is a new and a new respectively. If the thread is very long, one sphere does not disrupt the charge distribution on other sphere. we know, after connecting by a conducting thread the potential of the two-sphere are same, So, V = V2 Again, 2, +9 = 7+(-3) = 4ue= so, 21 new - Yue - a new d a new = (4x108 – 2, new ) a new = = 0.13 0.16 (4x10 6 – 9 new) C4 2 new = 0.8125 (4x10 6 - 2 new )

- q - 3.25 X10 - 0.8125 9. a new (1+0.8125) = 3.25x10 6 3.25x10 a qi new = 1.8125 = 1.793×10 k & 1.79x10 7 1.79 me Therefore , charge on sphere A is 1.29 uc And, 22 new = (4-1.79) me = 2.21 me Therefore charge on sphere B is 2.21 me