Question

two parter! THANKS FOR THE HELP

1) A conducting sphere of radius 13.0 cm has a net charge of 2.2 x 10^-8 C. What is the electric field at the surface of the sphere? Give your answer in N/C (equivalent to V/m).

2) A conducting sphere of radius 16.0 cm has a net charge of 2.8 x 10^-8 C. If V=0 at infinite distance, what is the electric potential at the sphere's surface? Give your answer in volts.

Answer 1

Solution:

Question (1) Solution:

Given:

Net Charge (Q) = 2.20 x 10^-8 C

and, r = 13.0 cm = 0.13 m

Therefore: the electric field at the surface of the sphere = kQ / r² = {(9 x 10⁹)(2.20 x 10^-8)} / (0.13)² = 11715.98 N/C

Question (2) Solution:

Given:

Net Charge (Q) = 2.8 x 10^-8 C

and, r = 16.0 cm = 0.16 m

Therefore: the electric potential at the sphere's surface = kQ / r = {(9 x 10⁹)(2.8 x 10^-8)} / (0.16) = 1575 V

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