charge q= -1.6 X 10^-19 C
Electric field = E = 3 N/C
Force F on electron = qE = -4.8 x 10^-19 Newtons
Distance moved = s= 15 cm = 0.15 m
We have,
Work done = Fscosθ
= 4.8 x 10^-19 x 0.15 x cos(90) (as the path of electron is perpendicular to the force on it)
= 0
Therefore Work Done on electron is 0
Option D is correct
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