What data should be plotted to show that experimental concentration data fits a first-order reaction? ln(k)...
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What data should be plotted to show that experimental concentration data fits a first-order reaction?
ln(k) vs. Ea
ln[reactant] vs. time
ln(k) vs. 1/T
1/[reactant] vs. time
[reactant] vs. time
Homework Answers
![Answer is (b) en [reactant] us, time a In [reactant] Intercept = ena Slope --k t This plat shows the first-order reaction Kin](http://img.homeworklib.com/questions/c11243d0-cf3a-11eb-85a7-a5a7a4ae80cd.png?x-oss-process=image/resize,w_560)
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What data should be plotted to show that experimental
concentration data fits a first-order reaction?
ln(k)...
Whole page please 81 What data should be plotted to show that experimental concentration data fits...
Whole page please
81 What data should be plotted to show that experimental concentration data fits a second- order reaction? ANSWER: A) 1/(reactant) vs. time B) [reactant) vs. time C) In[reactant) vs. time C) In(k) vs. 1/T E) In(k) vs. Ea 9) Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = k [X]2[M3 ANSWER: 10) A reaction is followed and found to have a rate constant of 3.36...
please help with these two question please QUESTION 24 What data should be plotted to show...
please help with these two
question please
QUESTION 24 What data should be plotted to show that experimental concentration data fits a second-order reaction? O In(k) vs. 1/1 O 1/[reactant) vs. time O In[reactant) vs. time O [reactant) vs. time In(k) vs. Ea QUESTION 25 The slope and intercept of an Arrhenius plot made for the first-order decomposition reaction are -9485.7K and 27.882 at 303K, what is the value of the activation energy (KJ/mol) at this temperature? *Please report 3...
The rate law of a reaction is rate =k[X]³. The units of the rate constant are
1)The rate law of a reaction is rate =k[X]³. The units of the rate constant areL mol-1 s-1mol² L-2 s-1mol L-1S-2L² mol-2 s-1mol L-1S-12)Given the following rate law, how does the rate of reaction change if the concentration of Z is tripled? Rate =k[X]³[Y]²[Z]⁰The rate of reaction will increase by a factor of136803)What data should be plotted to show that experimental concentration data fits a first-order reaction?1 / [reactant] vs. time[reactant] vs. timeln (k) vs. Ealn (k) vs. 1 / Tln [...
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they...
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k−k 1 ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 ln[A] vs. tln[A] vs. t −k−k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t kk A.) The reactant concentration in a zero-order reaction was 0.100 MM after 165 ss and 4.00×10−2 MM after 305 ss . What is the...
The experimental data for a Zero order chemical reaction at 25°C is plotted graphically with the...
The experimental data for a Zero order chemical reaction at 25°C is plotted graphically with the resulting linear equation: [C] = 100 - 2t. Where t is in minutes and concentration[C] is in mg/L 1. Determine how long is needed to achieve 95% degradation 2. Determine the half life of the reaction in minutes. 3. If O is 1.2 what is the kinetic constant at 35°C 4. Determine the half life at 35°C.
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they...
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k 1 ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 ln[A] vs. tln[A] vs. t −k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t k Part A The reactant concentration in a zero-order reaction was 8.00×10−2 MM after 130 ss and 4.00×10−2 MM after 380 ss . What is...
For a first order reactiomA-----> B, rate constant k for the reaction follows the equation: ln...
For a first order reactiomA-----> B, rate constant k for the reaction follows the equation: ln k= (5000/T) + 13.82 find the frequency factor A and the activation energy Ea
Q-4 (7.10). The concentration of a reactant in a first-order chemical reaction that proceeds at a...
Q-4 (7.10). The concentration of a reactant in a first-order chemical reaction that proceeds at a rate k can be described as follows: In(C) = ln(Co) - kt, where C is the concentration of the reactant at time t, Co is the initial concentration and t is the elapsed time since the reaction started. Consider an initial concentration of Co = 0.3 mol/L. The experiment was repeated n times to give a geometric mean of the concentration at time t...
Most of the time, the rate of a reaction depends on the concentration of the reactant....
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
The concentration of reactant A (in M) in a reaction of A → products was monitored...
The concentration of reactant A (in M) in a reaction of A → products was monitored as a function of time. The experimental data were plotted in three graphs of [A] versus time, ln[A] versus time, and 1/[A] versus time as shown. Determine the reaction order. Reaction order graph Not enough information to determine the reaction order. Zero order First order Second order Not enough information to determine the reaction order. 0.8 0.6 0.4 0.2 3 -2 0 2 46...
Whole page please
81 What data should be plotted to show that experimental concentration data fits a second- order reaction? ANSWER: A) 1/(reactant) vs. time B) [reactant) vs. time C) In[reactant) vs. time C) In(k) vs. 1/T E) In(k) vs. Ea 9) Given the following rate law, how does the rate of reaction change if the concentration of Y is doubled? Rate = k [X]2[M3 ANSWER: 10) A reaction is followed and found to have a rate constant of 3.36...
please help with these two
question please
QUESTION 24 What data should be plotted to show that experimental concentration data fits a second-order reaction? O In(k) vs. 1/1 O 1/[reactant) vs. time O In[reactant) vs. time O [reactant) vs. time In(k) vs. Ea QUESTION 25 The slope and intercept of an Arrhenius plot made for the first-order decomposition reaction are -9485.7K and 27.882 at 303K, what is the value of the activation energy (KJ/mol) at this temperature? *Please report 3...
The experimental data for a Zero order chemical reaction at 25°C is plotted graphically with the resulting linear equation: [C] = 100 - 2t. Where t is in minutes and concentration[C] is in mg/L 1. Determine how long is needed to achieve 95% degradation 2. Determine the half life of the reaction in minutes. 3. If O is 1.2 what is the kinetic constant at 35°C 4. Determine the half life at 35°C.
Q-4 (7.10). The concentration of a reactant in a first-order chemical reaction that proceeds at a rate k can be described as follows: In(C) = ln(Co) - kt, where C is the concentration of the reactant at time t, Co is the initial concentration and t is the elapsed time since the reaction started. Consider an initial concentration of Co = 0.3 mol/L. The experiment was repeated n times to give a geometric mean of the concentration at time t...
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
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