How many liters of chlorine gas at 25°C and 0.950 atm can be produced by the...
How many liters of chlorine gas at 25 C and 0.950 atm can be produced by the reaction of 0.0460 mol of MnO2 with 0.284 mol HCL according to the following chemical equation? Show all steps. MnO2+4HCL = MnCl2+2H2O+ Cl2
got this wrong, can someone please show solution to it. thank you 13. How many liters of çhlorine gas at 25 °C and 0.950 atm can be produced by the reaction of 0.0460 mol of MnO2 with excess HCI(aq) according to the following chemical equation? MnC2(s)+ 4HCI(aq) → MnCl2(aq) + 2H:001)ỚCI2(g) eaces (A)36 × 103 L. B)0.138 L-C) 0:282 L . D) 1.18 L 3.55 L
Chlorine gas can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid. How much MnO2 should be reacted with excess HCl to obtain 275 mL of chlorine gas at 5.0 °C and 650 mmHg? Equation: MnO2(s) + 4HCl(aq) => MnCl2(aq) + 2H2O(l) + Cl2(g) a. 0.0103 g b. 0.837 g c. 0.896 g d. 249 g e. 681 g
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO2(s)+4HCl(aq)⟶MnCl2(aq)+2H2O(l)+Cl2(g) How much MnO2(s) should be added to excess HCl(aq) to obtain 285 mL Cl2(g) at 25 °C and 805 Torr? mass of MnO2: g
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO2(s)+4HCl(aq)⟶MnCl2(aq)+2H2O(l)+Cl2(g) How much MnO2(s) should be added to excess HCl(aq) to obtain 155 mL Cl2(g) at 25 °C and 755 Torr?
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described by the chemical equation MnO2(s)+4HCl(aq)⟶MnCl2(aq)+2H2O(l)+Cl2(g) How much MnO2(s) should be added to excess HCl(aq) to obtain 305 mL Cl2(g) at 25 °C and 775 Torr ?
Chlorine can be prepared in the labroatory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO2(s) + 4HCl(aq) ---> MnCl2(aq) + 2H2O(l) + Cl2(g) How much Mn2(s) should be added to excess HCl(aq) to obtain 395 mL Cl2(g) at 25 degrees C and 785 Torr?
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4HCl(aq)+MnO2(s)⟶MnCl2(aq)+2H2O(l)+Cl2(g) A sample of 43.7 g MnO2 is added to a solution containing 49.3 g HCl. What is the limiting reactant? HCl MnO2 What is the theoretical yield of Cl2? theoretical yield: g Cl2 If the yield of the reaction is 87.3%, what is the actual yield of chlorine? actual yield: g Cl2
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4HCl(aq)+MnO2(s)⟶MnCl2(aq)+2H2O(l)+Cl2(g) A sample of 36.7 g MnO2 is added to a solution containing 48.9 g HCl. What is the limiting reactant? MnO2 HCl What is the theoretical yield of Cl2? theoretical yield: g Cl2 If the yield of the reaction is 72.1%, what is the actual yield of chlorine? actual yield:
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4HCl(aq)+MnO2(s)⟶MnCl2(aq)+2H2O(l)+Cl2(g) A sample of 33.9 g MnO2 is added to a solution containing 45.5 g HCl. What is the limiting reactant? MnO2 HCl What is the theoretical yield of Cl2? theoretical yield: g Cl2 If the yield of the reaction is 86.9%, what is the actual yield of chlorine? actual yield