The theoretical yield of 1,2-epoxycyclohexane is _grams, when starting with 3.0 grams of trans-2- bromocyclohexanol. (Enter...
What is the theoretical yield of 1,2-epoxycyclohexane? The theoretical yield of 1,2-epoxycyclohexane is _______________ grams, when starting with 3.0 grams of trans-2-bromocyclohexanol. (Enter the number using 3 significant figures, i.e. 1.22) Given: 3.0 g of trans-2-bromocyclohexanol FW: 179.05 25 mL of 10% NaOH FW: 40 and density: 1.11 g/mL 1,2-expoxycyclohexane FW: 98.15
1) Write a stepwise mechanisms for the bromination of: a) trans-stilbene and b) cis-stilbene (substitute benzene rings by Ph-notation for convenience; e.g., stilbene could be written as Ph- CH=CH-Ph). I 2) Use (S) and (R) nomenclature to label all stereogenic centers in the above products (each has two stereogenic centers) in problem 1. Identify any enantiomers and meso-products. 3) Complete the following table including formula weights and grams and moles of reagents used in order to calculate a theoretical yield...
s References] TUTOR Limiting Reactants: Compare Reactant Moles The theoretical yield of a reaction is the amount of product obtained if the limiting reactant is completely converted to product Consider the reaction: 2 Fe(s) +3 Cl2(g) 2 FeCl3(s) If 19.85 g Fe is mixed with 14.22 g Cl2, calculate the theoretical yield (g) of FeCl3 produced by the reaction g Show Approach Show Tutor Steps Submit
Exercises lI: Stoichiometry and limiting reagents, theoretical yield and percent yield 1. Given the following reaction N2(g) +3H2(g)2NH3(g) (a) How many number of moles of ammonia can be formed from 0.25 moles of N, gas? (b) How many moles of H2 are needed to react with 0.25 moles of N2 gas? O If you begin with a gas mixture that contains 2.00 moles of N2 gas, and 3.0 moles of H2 gas, at the end of reaction, which reactant is...
NAME 1) For the reaction shown, find the limiting reactant and the theoretical yield in moles of potassium chloride (CI) with the following initial quantities of reactants: 14.6 mol K, 7.8 mol Cla 2 K{s} + Cla(g) – 2 KCl(s) 2) For the reaction shown, find the limiting reactant and the theoretical yield of the product (LiF) in grams for the following initial quantities of reactants: 10.5g Li and 37.2g F2 2 Li(s) + F2(g) → 2 Lif(s) 3) Consider...
NC HNO3 NC NO2 H2SO4. AcOH, 0°C Major Product Mass used (grams) Theoretical yield (grams) Mass obtained (grams) Nitrating agent is in slight excess 2.0 1.75 Yield (%) Moles used (mol) Moles expected (mol) Nitrating agent is in slight excess Relative Reactivity (1-fastest; 6-slowest) Using the data given, calculate the number of moles of starting material used (limiting reagent) and determine the theoretical yield. Finally given the amount of major product collected the % yield will be determined. I
What is the theoretical yield (in grams) of the product, Al2 O3 (101.962g/mol) when 15.0g of each reactant is allowed to react by the following equation? NOTE: This is a limiting reactant problem. 4Al(s) + 3O2(g) --> 2Al2O3(s)
2. Propose a detailed mechanism for the zinc mediated debromination of trans-1,2- dibromocyclohexane. [2] +ZnBra H2o Br dibromocyclohexane starting with 1 g of the dibromide. Calculate the theoretical yield in mass (g) and volume (mL) of cyclohexene for this reaction. Show your work. [3]
Calculate the percent yield if you start with 0.18 mL trans-cinnamaldeyde and 0.617 g benzyltriphenylphosphonium chloride in 2 mL 10 N NaOH and isolate 0.206 g (E,E)-1,4-diphenyl-1,3-butadiene. Show ALL your calculations! (Hint: first you need to compare the moles of the substrates to know which substrate is the limited reagent. Then you calculate the percent yield by comparing the moles of the product with the theoretical yield (moles of the limited reagent).)
Calculate the percent yield if you start with 0.18 mL trans-cinnamaldeyde and 0.617 g benzyltriphenylphosphonium chloride in 2 mL 10 N NaOH and isolate 0.206 g (E,E)-1,4-diphenyl-1,3-butadiene. Show ALL your calculations! (Hint: first you need to compare the moles of the substrates to know which substrate is the limited reagent. Then you calculate the percent yield by comparing the moles of the product with the theoretical yield (moles of the limited reagent).)