Question

Second run Calculations 8. AT (°C) for water (7-6) 9. Mass of water (4–3) 10. Heat (J) gained by water (Show calculations.) First run 3.2° Soa 2.90 516 11. Heat (J) lost by the metal Heat (J) lost by metal = Heat (J) gained by water (10) 12. AT (°C) for metal (5-7) 13. Specific heat of the metal (J/g °C) (Show calculations.) muxim Tool 14. Identity of metal 10

Answer 1

2.9% 810T/°C) for water 9 mass of water 3.2% sog rater sig to Heat (3) gained 672 I 621.185 Meat gained is given by, Q = mest - and up= specific heat of water whose value is ' 4.2 5/806 You can find it in any book) ..Q for trial, = sox 4.283.2 672 J a for trial 2 - 5/8 4-2 X 2.9 627:18] 1 Heat (II lost by 6725 621-18 J the metal Given value to be AT/%) for To be find out metal vor to the experimentally. 13 Q = MEST To be find out Heat lost given - ou given dyl Compare the value of Le to the value of Epof mitt experimentally given man

Hope you like the solution.You have to compare the value of Cp to the standard Cp value of the metals and find the metal whose Cp value matches your Cp value and that metal is your desired metal.If you have any further queries,you can ask in the comment box and i will definitely have them solved for you.Please hit the like button,please.