Question




Problem 16.33 (a) A compound U (CH100) gives a negative lodoform test. The IR spectrum of U shows a strong absorption peak at
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Steps calculation of double band equalul - MF-cah,oo DOES (+- . 9+1 -0. 5 step- . Intepretation of Nur SH mutelplet at 7-7 da1 2 Isomer of u tv I-143 Ik bena urowser kelar 1705 SCH 9.0 13.5 were show mend which has refiers) group ch Scanne cocwit for

Add a comment
Know the answer?
Add Answer to:
Problem 16.33 (a) A compound U (CH100) gives a negative lodoform test. The IR spectrum of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Problem #23: When compound X (C,H,Br) is reacted with sodium cyanide (NaCN) forms compound Y (C,H...

    Problem #23: When compound X (C,H,Br) is reacted with sodium cyanide (NaCN) forms compound Y (C,H,N). Compound Y, upon reduction with H over a Ni catalyst, yields compound Z (C,HIN. The 'H NMR spectrum of X gives two signals, a multiplet at δ = 7.3 ppm (5H) and a singlet at δ 4.25 ppm (2H). The 'H NMR spectrum of Y is similar to that of X in that it shows a multiplet at ö-7.3 ppm (5H) and a singlet...

  • Compound A (C11H16O) has a band in the IR spectrum at 3450 cm-1 (strong, broad) and...

    Compound A (C11H16O) has a band in the IR spectrum at 3450 cm-1 (strong, broad) and does not react with pyridinium chlorochromate (PCC) in CH2CI2. Compound A does react with HBr to give compound B (11H15Br). Compound B reacts with potassium f-butoxide to give compound C (C11H14). Ozonolysis of C followed by treatment with Zn and water gives CH3CHO and compound D (C9H10O). The proton NMR spectrum of compound D is given below. Treatment of compound D with ethyl magnesium...

  • The mass spectrum of compound A shows molecular ion peak at m/z 88. The IR spectrum...

    The mass spectrum of compound A shows molecular ion peak at m/z 88. The IR spectrum of this compound has a broad peak between 3200 and 3550 cm-1. The 1H NMR spectrum of A shows the following peaks: a triplet at d 0.9, a singlet at d 1.1, one more singlet at d 1.15, and a quartet at d 1.6. The area ratio of these peaks is 3:6:1:2. The 13C NMR contains 4 signals. In the space below, propose a...

  • A compound, C,H100, shows an IR peak at 1690 cm. Its 'H NMR spectrum has peaks...

    A compound, C,H100, shows an IR peak at 1690 cm. Its 'H NMR spectrum has peaks at delta 7.9 (2H, multiplet), 7.6-7.4 (3H, multiplet), 2.95 (2H, quartet, J = 7 Hz), 1.25 (3H, triplet, J= 7 Hz). Draw its structure in the window below. . You do not have to consider stereochemistry. ChemDoodle A compound, C3H100, exhibits IR absorption at 1730 cm-1. Its carbon NMR shifts and substitution, determined by DEPT, are given below. 13C NMR: 822.6 (3), 23.6 (1),...

  • 14. An unknown compound shows an intense IR absorption at 1710 cm- and gives the following...

    14. An unknown compound shows an intense IR absorption at 1710 cm- and gives the following NMR spectrum: 8 1.1, doublet, 6Hs; 8 2.1, singlet, 3Hs; and 8 2.3-2.8, broad multiplet, 1H. Which structure is the compound? a) (CH3)2CHOCH3 с) CH:C-O)CH-CH-CH3 ect r b) CH3CH2CH2OCH3 d) (CH3)2CHC(O)CH3 15. This NMR spectrum corresponds to which compound? 2H 1H 1.7 ppm 1H O.5 1.5 1 2 2.5 3.5 4.5 4 5 бн (рpm) b) CH3CH2CH2CH2OH d) CH3CH2CH(OH)CH3 a) (CH3)3COH c) (CH)2СHCH,ОН 13

  • A compound, CyH,202, has an IR spectrum showing a peak at 1710 cm. Its 'H NMR...

    A compound, CyH,202, has an IR spectrum showing a peak at 1710 cm. Its 'H NMR spectrum has peaks at delta 1.3 (3 H, triplet), 4.3 (2 H, quartet), 6.5 (1 H, doublet), 7.4-7.6 (5 H, multiplet), and 7.7 (1 H, doublet). Draw its structure in the window below. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. . Do not include lone pairs in your answer. They will not be...

  • Problem 16.33 Show how you would convert benzaldehyde into each of the compounds using the reagents...

    Problem 16.33 Show how you would convert benzaldehyde into each of the compounds using the reagents (A - G) in the table below where necessary. H20+ PBrz NaBH4 A: (1) AICI: (2) H307 SOCI2 Ag(NH3)2 NHz/H20 B: C: D: LiAIH4 E: F: G: X Incorrect. (c) C6H5CHENNHC6H5 + CH stereoisomer (E)-1-phenyl-2-(phenylmethylidene)hydrazine A: PPhz Edit H3C X Incorrect. (d) CGHSCH=CHCH=CH2 H B (a Wittig reagent) B: ? Edit Problem 16.49 Compounds W and X are isomers; they have the molecular formula...

  • Question 45 1. a) NMR spectrum of CH3-CH2-O-CH3 contain one singlet, one quartet, and one triplet:...

    Question 45 1. a) NMR spectrum of CH3-CH2-O-CH3 contain one singlet, one quartet, and one triplet: True/False True False Question 46 1.b) CHCI-CHBr2: two doublets (d) will appear in the NMR spectra: True/False True False Question 47 1.c) CH3-CH2-CO-CH2-CN: IR spectra will show a peak at 1740 and 2200cm-1: True/False True False Question 48 1 pts 1.d) NMR of the above molecule will show two triplets and one singlets: True/False True False Question 49 1 pts 1. e) Or, one...

  • The IR/spectrum shows the value, 1st photo shows the instructions. Attached are 2 sets of spectra....

    The IR/spectrum shows the value, 1st photo shows the instructions. Attached are 2 sets of spectra. Each set is worth 25 points. Not all sets have a Mass Spectrum, but do have information that was obtained from MS and some sets do not have a "C-NMR and don't really need one. Look at each spectrum individually and clearly list and comment on the structural Characteristics you can determine from that spectrum. (Chemical shifts, splitting patterns, coupling constants, fragmentation patterns, absorption...

  • NMR, please help. 16) Chemical Formula: C,H,O, IR: strong peak 1720cm-1 PPM mple A4 thouis Yoo...

    NMR, please help. 16) Chemical Formula: C,H,O, IR: strong peak 1720cm-1 PPM mple A4 thouis Yoo 05 quadret 1:2:2:1 Triplet 1:3:1 244 PPM USER: -- DATE: 04/12/10 08:27 PTS1d: 4096 Nuts - A4 OF1: 372.1 010 AlglobalVZGH.ppg SWI: 1000 PW: 19.6 us PD: 3.0 sec NA LB: 0.0 (ethylacetate) H3C CH₂ - CH3 C4H8O₂ 2. PROTON MAGNETIC RESONANCE SPECTRAL DATA Complete the table below by listing the chemical shiits of all of the signal patterns in the nmr spectrum of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT