Question

solve all to get thumps up. no work is needed.

Question 6 1 pts What is the oxidation number of chromium in K2Cr2O7? +6 O +3 +12 O +7 +14

Answer 1

Question 6 K₂ Cr ₂ Oq => (+1) X 2 + 2x + (-2)X 7=0 => 2 + 2n -14 = 0 2n - 12=0 n = 12 = option (A) +6 +6 Question ? S, 03- - 2n + (- 2x3 = -2 27 - 6= -2 27 = -2 + 6 2x = + 4 n = 4 2 a =+2. option (A) ~ +2

Multiply by 6 in below equation. to balance, the elections (Fe 2+ (aq) - Fe3+ (as) + ê ) x 6 6 Pezt cas) 6fe3t (ap) & b é -1 Taking equation 6 & 6 we get, 2 CY Gê + 14H7 cap) + (80% (af) 2 Cr3+ (aq) + 7 Hoe ore 21 cas) - 6fe3t tag) + Gé 14 H+ (aq) + (0,0,? ( 29 )+ 6fe2+ (aq) + 2 Cost cave) + 7400 4 66 3t The offi coefficient of the dicheomate ion. Option (A) al

Question 8 Step I write the unbalanced ionic equation reat caght (ry of lagt res taqst (2 3+ (aq) Step I oxidation : re 2t cash re3t (as) Reduction : Cr, o cast Cost Cag! Step 1 → Get cr, 02- Cagl 2 C2 3+ (ap! Step IV - co012 last I (802 - Cast 2 Cg3 toppt Hold) In audic medium add Htions 1.4H+ (aq) + Cr₂02 lag! → 263+ (aq) + TH₂011) - Step I - Fe 2+ (ag) re 3t (as) + ē bě + 14H+ (aq) + er, of cap! 262 31 (ap) + 7 Holl) TV

Question 6 K₂ Cr ₂ Oq => (+1) X 2 + 2x + (-2)X 7=0 => 2 + 2n -14 = 0 2n - 12=0 n = 12 = option (A) +6 +6 Question ? S, 03- - 2n + (- 2x3 = -2 27 - 6= -2 27 = -2 + 6 2x = + 4 n = 4 2 a =+2. option (A) ~ +2