Question

= Knowledge Check Question 4 The vapor pressure of Substance X is measured at several temperatures: temperature vapor pressure - 79. °C 0.148 atm -- 70. °C 0.208 atm -61. °C 0.283 atm Use this information to calculate the enthalpy of vaporization of X. Round your answer to 2 significant digits. Be sure your answer contains a correct unit symbol. 0.0 . x 5 ?

Answer 1

Dear student,

cation, The vapour press wee es ginen at two different temperature we can use the Clausis Clapeyson equation to calculate enthalpy of vaporizati m( ) = - Shwal (7 - 17/2) where Pupe = Pressures in atom TiTz - Temperature in k R = 8,314 J / K-mol.. Stvap = enthalpy og vapowrization. Now, Ti=-79°C - - 79 +273 k = 1941 Tz=-70°c =-70+273k = 203k T3=-61°C =-61.+273k = 212k P = 0.148 atm P2 = 0.208 atm P₂ = 0,283 atm.

putting these values in ego 11 we get ( 203 ks) & un 10.148 afte) = - A Huap - 10.208alon 1 8,314 I 194K mol-4 +0.3403 - AH vap x1 203-194. 8,314 J/mol ( 1948203 ) J x 11948 203 • Hvap = 0.3403x8,314 mol 1203-1941 Hvap = 12380:19 Ional Athrop = 1.2 x 104 J/mol

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