Question

A student performed a titration in which aqueous NaOH (concentration = 0.1000 mol/L) was added via burette to a 25.00 mL aliq

0 0
Add a comment Improve this question Transcribed image text
Answer #1

At end point concentration of HCl solution is = .01*24.01/25

= 0.0096 mol/L

now concentration of Cl- ion is = 0.0096825/49.01

  = 0.004899 mol/L

   = 0.005

Add a comment
Know the answer?
Add Answer to:
A student performed a titration in which aqueous NaOH (concentration = 0.1000 mol/L) was added via...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1. A student carries out a back titration to determine the concentration of ammonium chloride in a solution. The student...

    1. A student carries out a back titration to determine the concentration of ammonium chloride in a solution. The student collects 10.80 mL of the original NH4Cl solution and dilutes it to 250.0 mL (we will refer to this as the dilute NH4Cl solution). Then 25.00 mL of the dilute NH4Cl solution are transferred to an Erlenmeyer flask and 25.00 mL of 0.1963 M NaOH are added. Calculate the moles of NaOH added to this Erlenmeyer flask. 2. In the...

  • A chemist had a bottle of HCl (aq) of unknown concentration. She performed a titration experiment...

    A chemist had a bottle of HCl (aq) of unknown concentration. She performed a titration experiment in order to determine its concentration. She pipeted 25.00 mL of the HCl solution into an Erlenmeyer flask. She then added about 21 mL of deionized water and 3 drops of phenolphthalein indicator dye to the flask. She titrated this mixture with 0.09063 M NaOH (aq), and obtained a permanent, pale pink endpoint after the addition of 36.68 mL of NaOH (aq). Given that...

  • 1.639 g of an unknown diprotic acis are used to make a 100.00 mL solutiob. Then...

    1.639 g of an unknown diprotic acis are used to make a 100.00 mL solutiob. Then 25.00 mL of this solution is trasferred to an Erlenmeyer flask and is titrated with 0.1008 M NaOH. The titration endpoint is reaxhed after 0.00432 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct nuber of significat figures 1.639 g of an unknown diprotic acid are used to make a...

  • Question 6 (1 point) 1.681 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of th...

    Question 6 (1 point) 1.681 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an Erlenmeyer flask and is titrated with 0.1047 M NaOH. The titration endpoint is reached after 0.00411 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct number of significant figures. Your Answer: Answer units

  • 1.639 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred...

    1.639 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an Erlenmeyer flask and is titrated with 0.1032 M NaOH. The titration endpoint is reached after 0.00414 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct number of significant figures.

  • Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial...

    Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 1.40/1.30 28.20 29.10.26.1026.50 Volume of NaOH added Initial buret reading Final buret reading Moles of NaOH added Moles of HCl reacted Molarity of diluted HCI Molarity of undiluted HCI Average molarity of undiluted HCI Precision PROCEDURE 1. Obtain approximately 40 mL of an unknown acid in an Erlenmeyer flask from your teaching assistant. 2. Clean your 250-ml volumetric flask (contains exactly 250.00...

  • Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 1...

    Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 11.40/1.30 28.20 29.10.26.1026.50 Initial buret reading Final buret reading Volume of NaOH added Moles of NaOH added Moles of HCl reacted Molarity of diluted HCI Molarity of undiluted HCI Average molarity of undiluted HCI Precision PROCEDURE 1. Obtain approximately 40 mL of an unknown acid in an Erlenmeyer flask from your teaching assistant. 2. Clean your 250-ml volumetric flask (contains exactly 250.00...

  • Worksheet 2 2. Calculate the concentration of each of the following solutions. Determine the molarity (mol/L)...

    Worksheet 2 2. Calculate the concentration of each of the following solutions. Determine the molarity (mol/L) of a solution made by diluting 5.880 g of barium chloride to a final volume of 525.0 mL a. b. What is the molarity of a solution that dilutes 12.50 mL of 6.00 M HCI (hydrochloric acid) to a final volume of 1.50 L? If you combine 1.55 g of NH CI (ammonium chloride) with 2.38 g of CaCl, (calcium chlo- ride) and dilute...

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT