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A student performed a titration in which aqueous NaOH (concentration = 0.1000 mol/L) was added via burette to a 25.00 mL aliq

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Answer #1

At end point concentration of HCl solution is = .01*24.01/25

= 0.0096 mol/L

now concentration of Cl- ion is = 0.0096825/49.01

  = 0.004899 mol/L

   = 0.005

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