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[2] (a) Consider the reaction of methane, CH4, burning in the presence of oxygen at constant pressure. Given the following eq

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Solution [2] as Molecules Mass of methane : CH4 = (12x1 + 1x4) = 16 goo/mol Therefore, 16 gm c Hy = 1 mole methane 15 gm CtyHence, volume of sulfur dioxide is 538.75 m. [3] (a) chemists creats new molecules, new materials, uncover new Phenomena, and

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