Question 4 (1 point) How many atoms are in 4.39 g of CO2? (molar mass 44.01...

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Question

Answer 1

Answer #1

No.of moles of CO₂= (4.39 g) / (44.01 g/mol) = 0.09975 mole

No.of atoms = 3

Therefore, No.of atoms in 4.39 g of CO₂ will be:

No.of atoms = (3 x 0.09975 mol) x (6.022 x 10²³ atoms/mol)

No.of atoms = 1.802 x 10²³ atoms -------- (ANSWER)

Answer 2

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