Question

15) What mass (g) of potassium chloride is contained in 430.0 mL of a potassium chloride solution that has a chloride ion concentration of 0.193 M? A) 0.0643 B) 0.0830 C) 12.37 D) 0.386 E) 6.19 16) What volume (mL) of 0.135 M NaOH is required to neutralize 13.7 mL of 0.129 M HCI? A) 13.1 B) 0.24 C) 14.3 D) 0.076 E) 6.55

please answer all questions and show work?

Answer 1

15 solution Part I :- volume ok kel=430ml 1000 ml = 1 Liter 1 mi= L Jooo Liter ao volume of Kel = 430 liter looo volume of Kel = .430 Liter part - I convert moles to gram Molar mass of kcl =74-55139 0.193 mol kc x 74.5513 gkel tool. KGA -14.3884 g kell 0.193 m ob Kol = 14.3884 a Kel

| O. 43 сок о. 143 Mok KC) = o.43 x јЧ. 3884 g Kc| — 6. 17 акс) І - 6. ја з кс) о. Аз оо. 133 Mob kel = 6 19 9 Кс

16 solutions Given For Hol M,= 0.129 M Ni 13.7 mi for Naon M2 = 0: 135 M V2 = ² ( to find) ... Mive = M2 V.2 v2 = Miti M2 v2 = 0.129 M X 13.7 mi 0.135 M v2 = 1.7673 mi 0.135 V2 = 13.og me V2 = 13.1 me
Answers -

15.

E) 6.19

16.

A) 13.1