Question

Tr=K' [A] ² [B]) Is the rate law for this mechanism consistent with the experimental rate law? Yes, this rate law is consistent with experimental rate law, the Let's jump back to Part 1 for three bonus points. Recall the chemical equation for the equilibrium reaction. DLP(aq) + 20 vp 7(aq) RLP(aq) Suppose after reaching equilibrium you added more RLP. Would the reaction shift to the left (towards reactants) or shift to the right towards products)? LEFT Suppose after reaching equilibrium you rapidly diluted the solution by adding more water. Would the reaction shift to the left (towards reactants) or shift to the right towards products)? RIGHT Explain how you reasoned out your answer to the dilution question? if you dilute it you are decreasing the concentration and increasing the volume, you are also inereasing the pressure.
is this correct?

Answer 1

Answers:-

DLP (aq) + 20vp7 (aq) -------> RLP (aq)

(i). After reaching equilibrium if we add more RLP. Then according to LE​​​ CHATELIER'S principal,if the concentration of products is increased then reaction would shift to reactant side to regain equilibrium.so reaction will shift to the left.

(ii). After reaching equilibrium if we rapidly dilute the solution then volume will be increased.If volume is increased pressure decreases hence reaction will shift in the
direction in which pressure increases that is in the direction in which number of moles increases and vice versa. Here number of moles is more on the reactant side is more and product side is less so equilibrium will shift towards right i.e on forward direction.

(iii). As already solved in part (ii)

According to le chatelier's principal..

Effect of volume.

If volume is increased pressure decreases hence reaction will shift in the
direction in which pressure increases that is in the direction in which
number of moles of gases increases and vice versa.

If volume is increased then, for
∆n > 0 reaction will shift in the forward direction
∆n < 0 reaction will shift in the backward direction
∆n = 0 reaction will not shift.

Where n = number of moles.

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