Question

Be sure to answer all parts. Balance the following skeleton reaction and identify the oxidizing and reducing agents: MnO4 (aq) + HCOOH(aq) - Mn2(aq) + CO26) [acidic] The oxidizing agent is: The reducing agent is:

Answer 1

+42 Mocaa) + HCOOH craq) - Cad) + ) ACIDIC MEDIUM I First show the oxidation number of every element I 3 + Ha t e the I Now we can split it as two half reactions I by the ondation half reaction and rednition half reaction. 4 colott & tał Whou + 50 - Morget → Now we have to balance the atoms in each half reaction. I first balance all other atoms except it, and on => Coo' c +27 +7+2 . Wno- +5e moet I Now we have to balance charge For a reaction in acidic medium, Balance the charge so that both sloe have the same local charge +2 4+ AMOR

siele By adding Htion in the defficient the charge 5 +2 + 2H mono +50 +8H+ 2+ → Now Balance of by adding Hao 01" *+ 2ē + 2H mod +5ł + 8Ht net + 4H₂O * Now we have to make sure that geun of a la red half reaction - loss of ē in onid hals reaction 2004 + 0 ² + 2ē + 2 H+ x 5 og - +50 +847 m 32 + 4H60 - x2 5 HCOOH 500 + 10€ + 104T a mnoy + 100 + 16412mm + +840 Now combine these two half reaction.

a coouMnO4 100 160t > 15 Coot & Maat 100 + Engroit Simplicy this and we will get 5.HCOOH + WMO + 6H! --> 00 ron can + Choco • Oxidizing agent = mna Here, mnou to moht, the and number reduced, so it gained es. Gaining of electron means oxidizing agenic • Reducing agent HCool Increase in oxidation number = reducing agon

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