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How much heat is required to vaporize 30.8 g of water at 100 ∘C∘C? (ΔHvap(H2O)=40.7kJ/mol, Heat...

How much heat is required to vaporize 30.8 g of water at 100 ∘C∘C? (ΔHvap(H2O)=40.7kJ/mol, Heat capacity(H2O)=4.184J/g∘C)(ΔHvap(H2O)=40.7kJ/mol, Heat capacity(H2O)=4.184J/g∘C)

Express your answer with the appropriate units.

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Answer #1

mass of the water = 30,8% (m) = 0.0308Lg & H vap (H2O) = 40.7 kg/mol 40.7410 18*163 g/ug (10 = 2.268106 g/kg - Heat required

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