Question

The molar mass of a nonelectrolyte is 58.0 g/mol

The molar mass of a nonelectrolyte is 58.0 g/mol. Compute the boiling point of a solution containing 16.9 g of this compound and 600.0 g of water. 


The barometric pressure during the experiment was such that the boiling point of pure water was 99.725 °C.  

1 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
The molar mass of a nonelectrolyte is 58.0 g/mol
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The molar mass of a nonelectrolyte is 58.0 g/mol. Compute the boiling point of a solution...

    The molar mass of a nonelectrolyte is 58.0 g/mol. Compute the boiling point of a solution containing 22.7 g of this compound and 600.0 g of water. The barometric pressure during the experiment was such that the boiling point of pure water was 99.725 °C.

  • 1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g...

    1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g of solvent, the solution boils at 83.44 °C. The boiling point of the pure solvent and its Kb are 79.31 °C and 4.47 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. 2. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.898 g dissolved in 268.7 mL of water at 30.13 °C has an osmotic pressure of 68.1...

  • 3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved...

    3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...

  • Which of the following methods cannot be used to determine the molar mass of a nonelectrolyte?...

    Which of the following methods cannot be used to determine the molar mass of a nonelectrolyte? a)​measurement of the freezing-point depression of a solution of the compound b)​measurement of the boiling-point elevation of a solution of the compound c)​measurement of the osmotic pressure of a solution of the compound d)​measurement of the x-ray diffraction of a pure crystal of the compound e)​measurement of the pressure, temperature, volume, and mass of the compound in the gaseous state a)​1,1 b)​2,1 c)​1,2 d)​4,1...

  • 1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g...

    1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g of cyclohexane freezes at a temperature 9.50 ºC below the freezing point of pure cyclohexane. Calculate the molar freezing point depression constant, Kf, for cyclohexane. 2. The molar boiling point elevation constant for water is 0.512 ºC/m. What is the boiling point of a solution containing 673 g of water and 78.0 g of CaCl2? 3. A solution containing 32.0 g of an unknown...

  • Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g...

    Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g mL-1, a freezing point of 5.45°C, and a boiling point of 80.2°C. Its freezing point depression and boiling point elevation constants are: Kf = 5.07°C m-1; Kb = 2.53oC m-1. A solution was made by taking 33.88 g of an unknown nonelectrolyte and dissolving it in 175.0 g of benzene. The measured freezing point of the solution was 1.65oC. Calculate the molar mass of...

  • 579.5 g of Al(NO3)3 (molar mass = 212.996g/mol) was dissolved in 17.89 kg of water. What...

    579.5 g of Al(NO3)3 (molar mass = 212.996g/mol) was dissolved in 17.89 kg of water. What is the boiling point of this solution? Boiling point of pure water is 100.00 C and the boiling point constant is 0.510 C

  • A 83.5 g sample of a nonelectrolyte is dissolved in 250.1 g of water. The solution...

    A 83.5 g sample of a nonelectrolyte is dissolved in 250.1 g of water. The solution is determined to have a boiling point of 102.3 °C. What is the molar mass of the compound? (Kb for water is 0.510 °C/m).

  • 1) An aqueous solution containing 15.9 g of an unknown molecular (nonelectrolyte) compound in 103.0 g...

    1) An aqueous solution containing 15.9 g of an unknown molecular (nonelectrolyte) compound in 103.0 g of water was found to have a freezing point of -1.5 ∘C. Calculate the molar mass of the unknown compound. b) Determine the required concentration (in percent by mass) for an aqueous ethylene glycol (C2H6O2) solution to have a boiling point of 109.3 ∘C. c) What mass of salt (NaCl) should you add to 1.90 L of water in an ice cream maker to...

  • A sample of 2.00 g of the non-volatile compound urea, CO(NH2)2 (molar mass = 60 g/mol),...

    A sample of 2.00 g of the non-volatile compound urea, CO(NH2)2 (molar mass = 60 g/mol), is dissolved in 20.0 grams of water. What is the vapor pressure of water above this solution? The vapor pressure of pure water at the temperature of the experiment is 0.150 atm. a. 0.045 atm b. 0.010 atm c. 0.038 atm d. 0.146 atm e. 0.150 atm

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT