Question

Consider the reaction below. What is the limiting reactant when 52.0 g of ethene (C2H4, molar mass = 28.0 g/mol) and 128 g of oxygen (molar mass = 32.0 g/mol) are reacted? C2H4(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(g)

• CO2 Not the correct answer

• H2O

• C2H4

• O2 what I think is the answer, but I have doubts

Answer 1

© ogm. olar mass = 28 52 190) ual 32 520gm. of ethere. (G. Hy, molar mass = 28.0 9]pol) = No. of mole of CHu = 2 o mole - 11.857 moles: & 128 gm. of oxygen (molar mass=320 g/mol) = No. of mole of oxygen = 12 g moles - 4 moles. Now the giren xh is - C Hugoto029 200(g) + 2 HOcg). from the ear it is clear that I mole of Calty reacts with 3 moles of og to produce a mole. of coo & I mole of Ho... » I mole of Se Hy will react with 3 moles of oxygen. - Grote 11857 mole of a Hy will react with = 3x1.857 moles of Oz - 1857 Ca Hu will read with 5.57 mole of O2, But we have only a moles of oxygen so oxygen will be limiting reagent for this sx".