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What are the concentrations at equilibrium of a 0.15 M solution of HCN? What will be...

What are the concentrations at equilibrium of a 0.15 M solution of HCN? What will be the concentration of Cu2+(aq) at equilibrium? HCN(aq)<=>H+(aq) + CN–(aq) , Kc= 4.9 x 10-10

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X HON (aq) HCN is a week + H+ (aq) + CN- (aq) acid, it will not dissociate completely Since gnitial (+20) . C . At equilibriuHope you like my answer ;)

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