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3. Why did the acetic acid odor disappear after the addition of NaOH? Draw a reaction...
why did the acetic acid odor reappear after the addition of HCI?
why did the acetic acid odor reappear after the addition of HCI?
A "5% acidity" bottle of vinegar is approx. 0.875 M in acetic acid (Ka = 1.8x10^-5)....
A "5% acidity" bottle of vinegar is approx. 0.875 M in acetic acid (Ka = 1.8x10^-5). a) Determine the approx. pH and percent ionization of acetic acid in this solution. b) Some health experts recommend adding 1 tablespoon (1 ounce) of vinegar to 1 cup of water (a total of 8 ounces). Calculate the approx. pH and percent ionization of acetic acid in this solution. c) How many mL of 0.10 M sodium acetate would be needed to make the...
Part A What is the molarity of the acetic acid solution? The reaction is NaOH(aq) +...
Part A What is the molarity of the acetic acid solution? The reaction is NaOH(aq) + CH3CO2H(aq) +CH, CO2Na(aq) +H2O(1) IVO AEV O O ? M Submit Request Answer A 25.0 mL sample of vinegar (dilute acetic acid, CH3CO2H) is titrated and found to react with 94.7 mL of 0.200 MNaOH.
a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor)...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
5. Determine the average value for the molarity of the acetic acid in vinegar. Show your...
5. Determine the average value for the molarity of the acetic acid in vinegar. Show your calculation 6. Determine the deviation between each individual molarity for acetic acid and the average value from question 4, above. Notice that the formula below uses absolute values: you only care about how big the difference is not whether cach trial value was higher or lower than the average. Deviation = (individual trial value)-(average value from #5) Trial Ideviation Trial 2 deviation Trial 3...
Question 1 1 pts When acetic acid and sodium bicarbonate react, why does the total mass...
Question 1 1 pts When acetic acid and sodium bicarbonate react, why does the total mass decrease? the bubbling of the reaction mixture always causes spattering of the sodium bicarbonate which causes the overall mass to decrease. O a gas is released in the reaction so it's mass is not part of the reaction mixture after the reaction is complete some of the acetic acid gets consumed in the reaction which causes the overall mass to decrease the total mass...
Draw the products of the reaction of benzoic acid with NaOH (aq) and identify the conjugate...
Draw the products of the reaction of benzoic acid with NaOH (aq) and identify the conjugate acid and base in the products. Determine the direction of the equilibrium for this reaction and use pKa values to justify your answer. Is the organic product of this reaction water soluble? Why or why not? Using the chemicals provided, benzoic acid, Ethyl p-aminobenzoate, Fluorenone, Sodium Hydroxide, Hydrochloric Acid, Anhydrous Sodium Sulfate, Diethyl Ether , how might you convert this product back to the...
use condensed structural formulas to write the balance equation for the reaction of salicylic acid with...
use condensed structural formulas to write the balance
equation for the reaction of salicylic acid with acetic
anhydride.
Use the models to demonstrate the reaction
use condensed structural formulas to write the balance
equation for the reaction of salicylic acid with methanol.
Use the models to demonstrate the reaction
Describe the appearance of aspirin product
REPORT SHEET: ASPIRIN Name Partner(s) Date Section Instructor A. Molecular models Use condensed Ne condensed structural formulas to write the balanced equation for the reaction...
the concentration is .1000 M for NaOH. you cN disregard the second column. but there is...
the
concentration is .1000 M for NaOH. you cN disregard the second
column. but there is no further information.
equivalence point is 22.95. i dont have mL NaOH
this is all i have
DATA TABLE sor CHCOOH Trial Volume CHCOOH (ml) [NTOH (M) Equivalence point Md point (ML) (ml) NE 100CM 1000M a.so DATA ANALYSIS moles -(CX) 1. Calculate the number of moles of NaOH used in the reaction with the acetic acid (CH.COOH) solution . OOON NaoH 2. How...
Part A What is the molarity of the acetic acid solution? The reaction is NaOH(aq) + CH3CO2H(aq) +CH, CO2Na(aq) +H2O(1) IVO AEV O O ? M Submit Request Answer A 25.0 mL sample of vinegar (dilute acetic acid, CH3CO2H) is titrated and found to react with 94.7 mL of 0.200 MNaOH.
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
5. Determine the average value for the molarity of the acetic acid in vinegar. Show your calculation 6. Determine the deviation between each individual molarity for acetic acid and the average value from question 4, above. Notice that the formula below uses absolute values: you only care about how big the difference is not whether cach trial value was higher or lower than the average. Deviation = (individual trial value)-(average value from #5) Trial Ideviation Trial 2 deviation Trial 3...
Question 1 1 pts When acetic acid and sodium bicarbonate react, why does the total mass decrease? the bubbling of the reaction mixture always causes spattering of the sodium bicarbonate which causes the overall mass to decrease. O a gas is released in the reaction so it's mass is not part of the reaction mixture after the reaction is complete some of the acetic acid gets consumed in the reaction which causes the overall mass to decrease the total mass...
use condensed structural formulas to write the balance
equation for the reaction of salicylic acid with acetic
anhydride.
Use the models to demonstrate the reaction
use condensed structural formulas to write the balance
equation for the reaction of salicylic acid with methanol.
Use the models to demonstrate the reaction
Describe the appearance of aspirin product
REPORT SHEET: ASPIRIN Name Partner(s) Date Section Instructor A. Molecular models Use condensed Ne condensed structural formulas to write the balanced equation for the reaction...
the
concentration is .1000 M for NaOH. you cN disregard the second
column. but there is no further information.
equivalence point is 22.95. i dont have mL NaOH
this is all i have
DATA TABLE sor CHCOOH Trial Volume CHCOOH (ml) [NTOH (M) Equivalence point Md point (ML) (ml) NE 100CM 1000M a.so DATA ANALYSIS moles -(CX) 1. Calculate the number of moles of NaOH used in the reaction with the acetic acid (CH.COOH) solution . OOON NaoH 2. How...
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