The temperature of a 15.8 g sample of gold increases from 20.5°C to 37.9°C. If the specific heat of gold is 0.129 J/g-K, how many joules of heat are absorbed?
Specific heat is the needed to increase temperature of 1 g material by 1 °C.
Temperature change = 37.9° C - 20.5°C = 17.4 °C= 17.4°K
Heat = Mass × specific heat × ∆T
= 15.8 g × .129 j g-1K-1 ×17.4°K
= 35.46 joule
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