NEED ANSWER ASAP A sample of aluminum metal absorbed 11.2 J of heat. The temperature of...

Question

Question

A sample of aluminum metal absorbed 11.2 J of heat. The temperature of the sample increased from 23.2 °C to 30.5 °C. The spec NEED ANSWER ASAP

Answer 1

Answer #1

we know q= mc at (Heat) q= 111 2 I DT= 30.5-23.2 - 7.3 °C e = 0.90 olgoc Putting all values ДСП 11.2 = mx 0.90 X 7.3 ma 11.2

Answer 2

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