Question

Please help as soon as possible. Answer needs to be correct and work shown. Anyone willing to help will receive a very good review! Thanks in advance

Question 16 2 pts How much heat is required to warm 28.6 g of water from 22.0°C to 78.3°C? The specific heat of water is 4.184 J/gºC. This question requires supporting work with units and unit cancellations on a separate sheet of paper. turned into your instructor 2.63 kJ 6.74k) 9.37 kJ 2.60) 3.94 * 10'

Answer 1

Given :- mass of water = 28.6g

Initial temperature = 22.0°C

Final temperature = 78.3°C

Specific heat = 4.184 J/g°c

As,

Heat required = mass X specific heat X ΔT

= 28.6g X 4.184 J/g°c X 56.3°C

= 6737 J

= 6.74 KJ