Question

Mass of copper wire: 0.2605 Mass of filter paper. 0.5233 g Mass of filter paper + CuQ: 08319 g Mass of filter paper. 0.5005 g Mass of filter paper + Cu: 0.7300 g Calculate the following: o Mass of CuQ (Experimental Yield): Mass of CuO that could be produced from Cu wire (theoretical yield) % yield Cuo. SY For the next part, the theoretical yield is just your mass of % yield = experimental Yield a X 100 Theoretical Yield copper wire at the start. Mass of Cu (Experimental Yield) % yield (recovery) Cu www. www www

Answer 1

Ans: Provided values for Yield calculation

a. Mass of copper wire                       = 0.2605 g

b. Mass of filter paper                        = 0.5233 g

c. Mass of filter paper + CuO = 0.8319 g

d. Mass of filter paper                        = 0.5005 g

e. Mass of filter paper + Cu    = 0.7300 g

Experimental Yield: Mass of CuO             = (c – b) = 0.8319 – 0.5233 = 0.3086 g

To calculate the theoretical yield, we need to know the molecular weights and the balance reaction.

Cu + ½ O2 -- > CuO

Molecular weights

Cu           = 63.5 g/mol  

CuO       = 79.5 g/mol

One mole of Cu gives one mole of CuO.

63.5 g of Cu wire gives 79.5 g of CuO

So, 0.2605 g of Cu wire will give = (79.5 g / 63.5 g) * 0.2605 g = 0.3261 g of CuO

Theoretical yield of CuO = 0.3261 g

% Yield of CuO = (Experimental yield / Theoretical yield) * 100

                                = (0.3086 g / 0.3261 g) * 100

% Yield of CuO = 94.63 %

Yield (recovery) calculation for Cu

Theoretical yield (Mass of copper wire)                 = 0.2605 g

Experimental yield: Mass of Cu                 = (e – d) = 0.7300 – 0.5005 = 0.2295 g

% Yield (recovery) of Cu               = (0.2295 / 0.2605) * 100 = 88.1 %

% Yield (recovery) of Cu               = 88.1 %