Homework Answers
3 Na2CO3 (aq) + 2 Al(NO3)3 (aq) 
Al2(CO3)3 (s) + 6 NaNO3 (aq).
Insoluble product is Al2(CO3)3
Now, mole ratio of Na2CO3 to Al2(CO3)3 = 3:1
Now, moles of Na2CO3 reacted =
( mass/molar mass)
= ( 3.03/106)
= 0.029
Then, moles of Al2(CO3)3 formed = (0.029/3)
= 0.0095
Now, mass of Al2(CO3)3 formed
= Moles × molar mass
= 0.0095 (mol) × 234 (g/mol)
= 2.23 g.
So, correct answer is Al2(CO3)3 , 2.23 g
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