Question

Review Constants Periodic Table 1. Explain the difference in reactivity in substitution reactions between CH3Br and CH OH 2. Explain the difference in reactivity in substitution reactions between CH3 O H2 and CH3OH Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Reset Help acid H30+ CH3OH base 1. The conjugate of the leaving group of CH2Br is the conjugate of the leaving group of CH2OH is Because is a much stronger acid (pKA (PK = is a much weaker base than Br- Therefore, is a much better leaving HO to be much causing group than in a substitution reaction. more reactive than CH, OH,

the list of options are: acid, H30+, CH3OH, base, Br-, HO-, CH3O+H2, HBr, CH3Br, 15.7, -9, -1.7, H2O

Answer 1

The conjugate Acid of the leaving group of CH3Br is HBr. the conjugate Acid of the leaving group of CH3OH is H2O. Because HBr is much stronger acid (pKa -9) than H2O (pKa 15.7). Br- is much weaker base than OH-. Therefore Br- is much better leaving group than OH- , causing CH3Br to be much more reactive than CH3OH in a substitution reaction.

Note: weaker the base better the leaving tendency.