Question

Part 1: Specific Heat of Copper Metal Your Data Neighbor 1 Neighbor 2 Weight of copper taken, grams 24.724 g __ 24.916 g 25.124 g Weight of water taken, grams 49.591 g_ 50.129 g 24.983 g Temperature of heated copper, 100°C 100°C 100°C Temperature of cool water, °C 22°C 23.2°C 21.5°C Final temperature reached, °C 25.5°C 26.5°C 24.9°C Heat GAINED by water, Joules Heat LOST by copper, Joules Specific heat of copper, Joules/g°C Average value of specific heat of copper metal

Answer 1

Part 1: Specific Heat of Copper Metal

Heat gained by water (your data) = mass of water * specific heat of water * Change in temperature = 49.591 g * 4.18 J/gC * (25.5 - 22)C = 725.52 J

Heat gained by water (Neighbor 1 data) = mass of water * specific heat of water * Change in temperature = 50.129g * 4.18 J/gC * (26.5 - 23.2)C = 691.48 J

Heat gained by water (Neighbor 2 data) = mass of water * specific heat of water * Change in temperature = 24.983g * 4.18 J/gC * (24.9- 21.5)C = 355.06 J

Heat lost by copper will be equal to heat gained by water in each of the three (substitute the same value as calculated for your data, neighbor 1 and neighbor 2)

Specific heat of copper (your data) = 725.52/(24.724 * (100-25.5)) = 0.394 J/gC

Specific heat of copper (Neighbor 1) = 691.48/(24.916 * (100-26.5)) = 0.3776 J/gC

Specific heat of copper (your data) = 355.06/(25.124 * (100-24.9)) = 0.188 J/gC

average specific heat capacity = (0.394 + 0.378 + 0.188)/3 = 0.32 J/gC

Part 1: Specific Heat of Glass Beads

Heat gained by water (your data) = mass of water * specific heat of water * Change in temperature = 49.816 g * 4.18 J/gC * (28.2 - 21.5)C = 1395.15 J

Heat gained by water (Neighbor 1 data) = mass of water * specific heat of water * Change in temperature = 50.156g * 4.18 J/gC * (28.6 - 22.3)C = 1320.81 J

Heat gained by water (Neighbor 2 data) = mass of water * specific heat of water * Change in temperature = 49.978g * 4.18 J/gC * (27.5 - 20.8)C = 1399.7 J

Heat lost by copper will be equal to heat gained by water in each of the three (substitute the same value as calculated for your data, neighbor 1 and neighbor 2)

Specific heat of copper (your data) = 1395.15/(25.102* (100-28.2)) = 0.774 J/gC

Specific heat of copper (Neighbor 1) = 1320.81/(25.32* (100-28.6)) = 0.731 J/gC

Specific heat of copper (your data) = 1399.7/(24.868* (100-27.5)) = 0.776 J/gC

average specific heat capacity = (0.774 + 0.731 + 0.776)/3 = 0.7603 J/gC

Note - Post any doubts/queries in comments section.