Question

TOUARULUDWIVUIUHMAL2369ec05e16853b19f38eb79153910301 <Homework #11 Percent Yield Review Constant The Haber Bosch process is a very important industrial process. In the Haber-Bosch process, hydrogen gas reacts with nitrogen gas to produce ammonia according to the equation 3H2() + Na(s) - 2NH3(g) 1.44 H is allowed to react with 10.1 g N, producing 2.69 NH Part A The ammonia produced in the Haber-Bosch process has a wide range of uses, from fertilizer to pharmaceuticals However, the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation What is the theoretical yield in grams for this reaction under the giver conditions? Express your answer to three significant figures and include the appropriate units. View Available Hints) MÅ RO? Value Units Submit Part B What is the percent yield for this reaction under the given conditions? Express your answer to three significant figures and include the appropriate units. View Available Hints) Value Units Submit

Answer 1

mean Balanced chemical equation for formation of ammonia by Haber process is as below 3H₂ + N - 2NH2 It mean 3 mal of Ho react with I mol of Na to give a mol of Ammonia Os in other words (3 mol of He 6 gram) of Ha react with [28g = 1 mol Nal of Ne to give [2 mol = Bug] g NH3 . 3 & N - 2NH3 69 289 34g Now ig he react with 28g Ng to give 3416 g of Nity. os lung H₂ react with Na (28x1.4ug] to give 34 x 1.44g of Nig. So Theoretical yield = 34x1.44 = 8.163] Given Yield of reaction = 2.69 g So /. (bercentage) yield – 3:69 x 100 = (339.. 8.16