Question

suppose an ore sample contains 10.0 impurity in addition to a mixture of cus and cu2s. Heating 100.0g of the mixture produces 76.2g of copper metal with a purity of 90.4%. What is the weight percent of cus of the ore? The percent of cu2s?

Copper metal can be prepared by roasting copper ore, which can contain cuprite (CuzS) and copper(II) sulfide. Cu,S(s) + O2(g) + 2 Cu(s) + SO2(E) CuS(s) + O2(g) + Cu(s) + S02 (8) Suppose an ore sample contains 10.0% impurity in addition to a mixture of CuS and Cu S. Heating 100.0 g of the mixture produces 76.2 g of copper metal with a purity of 90.4%. What is the weight percent of Cus in the ore? The weight percent of Cu2S? Weight percent of Cus - % Weight percent of Cugs- % Submit Answer Try Another Version Item attempts remaining

Answer 1

objective is to determine the weight % aus weight % of cu,s. out of loogm , logn is impurition. Then rest 90 gm is usefeed. det os asscane X gm of cus and (90-x)gm of cus are presente gmol of cars glues Sulphure 39 and 63.5 mole of cler 63.5 +32 = 95.5 gm of cus given 63.5 gon giver of 'Cui Culos ( 63.5+ (2*32) = 159 g produces 127 gm of Cul gm and it is equal to (90-) 127 95.5 + - 159 to question 90.4 76.2 * gm accoding 90.4 Tod' 0.6651 - ( 90-2) 0.7987 = 76.2* (0.6658 - 0.7987 ) x + (90* 0.7987) = 68.8848 68.8848 0.1337x + 71.883 0.133 7% 2.9982 9.9982 10:1337 az * 0.1334

cus= (x= 22.424 } to weight & Icus 90-1= 67.57 % weight - to- -